java - Regular expression Notepad++ OK JDK 1.6 NOK -


as part of internship, have use regular expressions parse log file. it's java log , have problem detection of exceptions.

in fact, regular expression works on notepad++ not java (1.6), matcher.find() take very, ..., long time, , find 0 match finally.

this regular expression:

(.*\berror\b.*)\r?\n((\tat|.*[ee]xception|\t\.\.\.|\r?\n|ora-).*\r?\n)+(^(?!.*error).+)\r?\n

do know why ?

thanks.

back slash \ both escape character java programming language , regular expressions. therefore when slashes regular expressions inside java (and many other programming languages) have duplicate slash.

for example write \\s instead of \s requires syntax of regular expression.


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