java - Regular expression Notepad++ OK JDK 1.6 NOK -
as part of internship, have use regular expressions parse log file. it's java log , have problem detection of exceptions.
in fact, regular expression works on notepad++ not java (1.6), matcher.find() take very, ..., long time, , find 0 match finally.
this regular expression:
(.*\berror\b.*)\r?\n((\tat|.*[ee]xception|\t\.\.\.|\r?\n|ora-).*\r?\n)+(^(?!.*error).+)\r?\n
do know why ?
thanks.
back slash \
both escape character java programming language , regular expressions. therefore when slashes regular expressions inside java (and many other programming languages) have duplicate slash.
for example write \\s
instead of \s
requires syntax of regular expression.
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