c# - Get MethodInfo from expression without knowing method signature -

i'm trying pass expression describes method want argument typed , don't want have know method signature or pass arguments in expression, this:

getmethod<myclass>(c => c.dosomething); 

where dosomething have method signature this... string dosomething(int id, int count)

i know can this:

memberinfo getmethod<t>(expression<func<t, delegate>> expression);  //implementation getmethod<myclass>(c => new func<int, int, string>(c.dosomething)) 

but frankly, quite ugly.

is possible?

just have overload each possible action/func. won't cover all possibilities (have overload you've shown there cover edge cases) it'll handle of them.

the body of each of action/func overloads can call overload you've shown above actual implementation.

public memberinfo getmethod<t1, t2>(expression<func<t1, func<t2>>> expression) {     return getmethodimpl(expression); }  public memberinfo getmethod<t1, t2, t3>(expression<func<t1, func<t2, t3>>> expression) {     return getmethodimpl(expression); }  public memberinfo getmethod<t1, t2>(expression<func<t1, action<t2>>> expression) {     return getmethodimpl(expression); }  //... 

getmethodimpl can implemented so:

private memberinfo getmethodimpl<t1, t2>(expression<func<t1, t2>> expression) {  } 

that able slight modification of existing getmethod implementation. t2 delegate; may need cast delegate, depending on how use it.