c++ - Can I make a #define and use it in a throw? -

can make this?

#define n_valid "is not valid id"   ...   throw n_valid;   ...   catch(char *message){   fprintf(stderr,"%s",message);}   

yes, except throwing const char *, not char *: https://ideone.com/usnitg

#include <iostream> using std::cout; using std::endl;  #define n_valid "is not valid id"  void function_throws() {   throw n_valid; }  int main() {     try     {         function_throws();     }     catch(const char *message) // <= note const here!     {         cout << message << endl;     } } 

however, joel correct should avoid doing this. if want use macro here, try using argument std::exception object: https://ideone.com/dsx1rf

void function_throws() {   throw invalid_argument(n_valid); }  int main() {     try     {         function_throws();     }     catch(const invalid_argument& ex)     {         cout << "invalid_argument: " << ex.what() << endl;     } }