quartz scheduler - Cron Expression - Run every hour after a start time -

i want run cron job every hour after start time. cron job expression

cronexpression = seconds + " " + minutes +  " " +   hours +"/1" + " " + " * * ? *" ; 

(seconds, minutes, hours passed in user selection)

the job starts @ right time , runs every hour until midnight stops until hour on next day , resumes. how job continuously run , not stop @ midnight?

i understand can change expression

cronexpression = seconds + " " + minutes +  " " * * * ? *" ; 

but not take account start time. run @ every hour.

thanks in advance, rich

do mean want job start @ given time , run once hourly forever? if so, don't think cron expression right approach.

if you're using scheduler should straightforward start job , run forever @ given interval. example, here's snippet quartz scheduler docs jobbuilder:

     jobdetail job = newjob(myjob.class)          .withidentity("myjob")          .build();       trigger trigger = newtrigger()           .withidentity(triggerkey("mytrigger", "mytriggergroup"))          .withschedule(simpleschedule()              .withintervalinhours(1)              .repeatforever())          .startat(futuredate(10, minutes))          .build();       scheduler.schedulejob(job, trigger);