$.ajax() jquery how to send multiple data values -


this update of code. values in update statement, still parse error. maybe has var update variabele.

    $("#submit_tosolve").on("click",function(e)  { alert("ok");  $.valhooks.textarea = {   get: function( elem ) {     return elem.value.replace( /\r?\n/g, "\r\n" );   } };  // data uitlezen uit textarea var message =$("#bugcommentaar").val();  //ok //var solved_ajax=$('input:radio[status3]:checked').val(); //ok dit nog in datatype steken data: console.log(message);  var request = $.ajax({   url: "ajax/facebook_ajax.php",   type: "post",   data: {message : message}, //json   datatype: "json" });  request.done(function(msg) { if(msg.status=="success"){     var update='<div style="display:none;" class="span4">'+   ' <tr>'+'<td>'+'<textarea class="bugcommentaar">'   '<p>'+message+' <span> comment posted </span></p></textarea></tr></td></div>';  $("#comments tr").prepend(update); $("#comments tr td").first().slidedown(); //dit gaat werken op elke browser, de eerste eruit halen    } });  request.fail(function(jqxhr, textstatus) {   console.log("request failed" +textstatus); });  //hou submi tegen e.preventdefault();   });

here ajax code: in code wan't update var message. can't because need var message2 id.

 <?php     session_start();     include_once("../classes/bug.class.php");           if(isset($_post['message'])) // komt van app.js         {             try             {                 $bug = new bug();                 $bug->commentaar=$_post['message'];                 $bug->bug_id=$_session["id2sessioncommentaar"];                 $bug->updatecommentaar();                    $feedback['text'] = "your comment has been posted!";                 $feedback['status'] = "success";             }             catch(exception $e)             {                 $feedback['text'] = $e->getmessage();                 $feedback['status'] = "error";             }              header('content-type: application/json' );             echo json_encode($feedback);          }   ?>

hi please this..

var request = $.ajax({   url: "ajax/facebook_ajax.php",   type: "post",   data: { message : $("#bugcommentaar").val(),       messageid2: $("#id2").val()      },   datatype: "json" });

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