c# - How I get the Parametervalue of a xml for the treeview`? -

hi have xml , want show in treeview in c#

it works treeview don't show me want see.

i try explain problem:

here xml:

<?xml version="1.0" encoding="utf-8"?> <lm-x stat_version="3.32"> <license_path type="network" host="6200@lwserv005" server_version="4.4.4" uptime="53 day(s) 21 hour(s) 10 min(s) 50 sec(s)"> feature name="globalzoneeu" version="12.0" vendor="altair" start="2013-03-26" end="2014-03-31" used_licenses="111720" total_licenses="147000" share="custom ,virtual"> <user name="system" host="lwserv171" ip="172.16.11.115" used_licenses="2000" login_time="2013-04-17 12:42" checkout_time="2013-04-17 12:42" share_custom="hweuser:172.16.11.115"/> ... </license_path> </lm-x> 

i want in treeview structure how this: features

globalzoneeu hwaifpbs hwawpf ...

here c# code:

private void btnshowlicstate_click(object sender, eventargs e) {     string command = "\"c:\\lmxendutil.exe\" -licstatxml -host lwserv005 -port 6200";      string output = executecommand(command);     string final_output = output.substring(90, output.length-90);      xdocument doc = xdocument.parse(final_output);      buildtree(treelic, doc);        txtoutput.text = final_output;  }  static string executecommand(string command) {     int exitcode;     processstartinfo processinfo;     process process;      processinfo = new processstartinfo("cmd.exe", "/c " + command);     processinfo.createnowindow = true;     processinfo.useshellexecute = false;     processinfo.redirectstandarderror = true;     processinfo.redirectstandardoutput = true;      process = process.start(processinfo);      string output = process.standardoutput.readtoend();     exitcode = process.exitcode;      process.close();      return output;  }  private void buildtree(treeview treeview, xdocument doc) {     treenode treenode = new treenode(doc.root.name.localname);     treeview.nodes.add(treenode);     buildnodes(treenode, doc.root); }  private void buildnodes(treenode treenode, xelement element) {     foreach (xnode child in element.nodes())     {         switch (child.nodetype)         {             case xmlnodetype.element:                 xelement childelement = child xelement;                 treenode childtreenode = new treenode(childelement.name.localname);                 treenode.nodes.add(childtreenode);                 buildnodes(childtreenode, childelement);                 break;             case xmlnodetype.text:                 xtext childtext = child xtext;                 treenode.nodes.add(new treenode(childtext.value));                 break;         }     } } 

how can names of nodes example--->

<feature name="globalzoneeu" version="12.0" vendor="altair"  ...> 

i want name ...

not entirely sure want, looking

(string)childelement.attributes("name") 

instead of

childelement.name.localname 

?